From: spiros85 <spirosfr_1985@hotmail.com>
To: linux-c-programming@vger.kernel.org
Subject: C program help
Date: Sat, 19 Sep 2009 08:13:22 -0700 (PDT) [thread overview]
Message-ID: <25522429.post@talk.nabble.com> (raw)
Hi guys of dear forum!I am a new programmer in C programming language and i
have a question for you about the following C code:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int x;
int answer;
int right;
int wrong;
printf("This is a program of sum\n");
right = 0; /*Initialization of right value*/
wrong = 0; /*Initialization of wrong value*/
for(x = 1; x <= 10; x++)[QUOTE][/QUOTE]
{
printf("What is %d + %d: ", x, x);
scanf("%d", &answer);
printf("The sum is %d\n", answer);
printf("\a");
if(answer == x + x)
{
printf("%d is RIGHT answer\n", answer);
right++; /*Saves and increases the amount of right answers*/
}
else
{
printf("%d is WRONG answer\n", answer);
b[10] = answer;
wrong++; /*Saves and increases the amount of wrong answers*/
printf("The correct answer is %d\n", x + x);
}
}
printf("The right answers are %d and the wrong are %d\n", right, wrong);
fflush(stdin);
getchar();
}
First, I use DEV C++ compiler!This program asks from user to find the sum of
1+1,2+2 until for loop reaches 10.As you can observe with right++ and
wrong++ i can define and print to the screen the amount of right or wrong
numbers!
My question is how could I define the number of correct and wrong numbers in
collaboration with their amount?For example:
The right answers are 8 and wrong are 2
The right answers are 2 4 6 8 10 12 14 16
The wrong answers are 22 44
--
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Sent from the linux-c-programming mailing list archive at Nabble.com.
next reply other threads:[~2009-09-19 15:13 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-09-19 15:13 spiros85 [this message]
2009-09-19 15:38 ` C program help Tim Walberg
2009-09-19 15:51 ` Manish Katiyar
2009-10-09 12:10 ` shiva kumar
2009-12-29 4:50 ` vignesh1988i
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